Question

if m=2/3 and n=1/2.then find the value of

I)9m^2-8n^3
2)81m^3 + 4n^3- 9n^2​

Answer 1

$9 {m}^{2} - 8 {n}^{3} \\ 9 \times {( \frac{2}{3} )}^{2} - 8 \times {( \frac{1}{2} )}^{3} \\ 9 \times \frac{4}{9} - 8 \times \frac{1}{8} \\ 4 - 1 \\ 3$

$81 {m}^{3} + 4 {n}^{3} - 9 {n}^{2} \\ 81 \times {( \frac{2}{3} )}^{3} + 4 \times {( \frac{1}{2} )}^{ 3} - 9 \times {( \frac{1}{2} )}^{2}$

Answer 2

Answer: on solving you get 1) 3 and 2) 89/4= 22.25

Step-by-step explanation: