Question

if m^2-√5m+1=0 then prove that m^5-1/m^5=1​

Answer 1

Step-by-step explanation:

${m}^{2} - \sqrt{5} m + 1 = 0 \\ a = 1..b = - \sqrt{5} ..c = 1 \\ m= \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ = \frac{ \sqrt{5} + \sqrt{5 - 4} }{2} \\ = \frac{ \sqrt{5} + 1 }{2} \\ similarly.. \\ m = \frac{ \sqrt{5} - 1 }{2}$