If m^2=5m-3 ,n^2=5n-3 and m not equal n then what is value of mn?
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Answer:
m=5,n=1
Step-by-step explanation:
a^1/a^2=b^1/b^2=c^1/c^2
3/m+n=4/2(m-n)=12/5m-1
3/m+n=2m-n=12/5m-1
3/m+n=2/m-n
=3(m-n)=2(m+n)
=3m-3n=2m+2n
=m=5n-1
2/m-n=12/5m-1
2/5n-n =12/5(5n)-1
2/4n=12/25n-1
1/2n=12/25n-1
25n-1=24n
from 1 and 2
m=5
n=1
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