Math, asked by sreejakhoney, 1 day ago

if m=(-2) and n=2 find the following​

Attachments:

Answers

Answered by pushpaupadhyay0073
0

Answer:

this type you do other question

Step-by-step explanation:

please mark in the brain list

Attachments:
Answered by rksc
0

Answer:

The value of (i)=16 , (ii) = 17/4 , (iii) = 61/4 , (iv) = 22

Step-by-step explanation:

(i) m= -2 , n= 2

 m^{2} + n^{2} - 2nm

(-2)^{2} + (2)^{2} - 2×(-2)×2

 4+4+8

 16

(ii) mⁿ + n^{m}

(-2)^{2} + 2^{-2}

= 4+ 1/4

= 17/4

(iii) 6m^{-3} + 4n^{2}

   = 6×(-2)^{-3} + 4×2^{2}

   = 6/(-8) + 4×4

   = -3/4 +16

   = \frac{-3+64}{4}

   = 61/4

(iv) 2n^{3} - 3m

   =2×2^{3} -3×(-2)

   =2×8+6

   = 22

Similar questions