Question

If m=-2 and n = 2; find the value of:
(1 m2 + n2 - 2mn
(ii) m + nm
(iii) 6m-3 + 4n2
iv) 2n3 - 3m​

Answer 1

Answer:

m2 + n2 - 2nm = 8

m + nm = -6

6m-3 + 4n2 = 1

2n3 - 3m = 18

Answer 2

Answer:

Here,

• m = -2
• n = 2

Finding :

i) m² + n² - 2mn

→ -2² + 2² - 2 × (-2) × 2

→ 4 + 4 - 4 × (-4)

→ 8 + 16

→ 24

ii) m + nm

→ -2 + 2 × (-2)

→ -2 × (-4)

→ 8

iii) 6m - 3 + 4n²

→ 6 × (-2) - 3 + 4 × 2²

→ -12 - 3 + 4 × 4

→ -12 - 3 + 16

→ -15 + 16

→ 1

iv) 2n³ - 3m

→ 2 × 2³ - 3 × (-2)

→ 2 × 8 + 6

→ 16 + 6

→ 22

Note :

I corrected all the confusion of exponent and numbers that was present in the question.