Question

If m=-2 and n = 2; find the value of:
(1 m2 + n2 - 2mn
(ii) m + nm
(iii) 6m-3 + 4n2
iv) 2n3 - 3m​

plz answer fast

Answer 1

Answer:

Here,

• m = -2
• n = 2

Finding :

i) m² + n² - 2mn  

→ -2² + 2² - 2 × (-2) × 2

→ 4 + 4 - 4 × (-4)

→ 8 + 16

→ 24

ii) m + nm

→ -2 + 2 × (-2)

→ -2 × (-4)

→ 8

iii) 6m - 3 + 4n²

→ 6 × (-2) - 3 + 4 × 2²

→ -12 - 3 + 4 × 4

→ -12 - 3 + 16

→ -15 + 16

→ 1

iv) 2n³ - 3m

→ 2 × 2³ - 3 × (-2)

→ 2 × 8 + 6

→ 16 + 6

→ 22

Note :

I corrected all the confusion of exponent and numbers that was present in the question.

Answer 2

Answer:

(i) m² + n² - 2mn = 16

(ii) m + nm = (-6)

(iii) 6m^(-3) + 4n² = (61/4)

(iv) 2n³ - 3m = 22

Step-by-step explanation:

We have,

m = (-2)

n = 2

Then,

(i)

m² + n² - 2mn = (-2)² + 2² - 2(-2)(2)

v = 4 + 4 + 8

= 16

Hence,

m² + n² - 2mn = 16

(ii)

m + nm = (-2) + (-2)2

= (-2) + (-4)

= (-6)

Hence,

m + nm = (-6)

(iii)

6m^(-3) + 4n² = 6(-2)^(-3) + 4(2)²

= 6(-1/2)³ + 4(4)

= 6(-1/8) + 16

= (-6/8) + 16

= (-6/8) + (128/8)

= (128 - 6)/8

= 122/8

= 61/4

Hence,

6m^(-3) + 4n² = (61/4)

(iv)

2n³ - 3m = 2(2)³ - 3(-2)

= 2(8) + 6

= 16 + 6

= 22

Hence,

2n³ - 3m = 22

Hope it helped and believing you understood it........All the best