Math, asked by krazy4you, 9 hours ago

If m=-2, p=12, and r=3. What is the value of the expression?
topic: solving positive, negative and zero exponents

Answers

Answered by mayank2652
0

Answer:

your expression "a-2 b-3" is meant to be "(a-2)(b-3)" then Bill is correct, and the answer is -5 when a is 3 and b is -2.29-Dec-2012

Answered by pulakmath007
0

SOLUTION

COMPLETE QUESTION

Complete question is referred to the link :

https://brainly.in/question/48448039

If m = - 2, p = 12 , and r = 3. What is the value of the expression

\displaystyle \sf{   - 4 {m}^{0}  {p}^{ - 3}  {r}^{2} }

EVALUATION

Here the given expression is

\displaystyle \sf{   - 4 {m}^{0}  {p}^{ - 3}  {r}^{2} }

Now Putting m = - 2, p = 12 , and r = 3 we get

\displaystyle \sf{   - 4 {m}^{0}  {p}^{ - 3}  {r}^{2} }

\displaystyle \sf{   =  - 4 \times  {( - 2)}^{0}  \times  {(12)}^{ - 3}  \times  {(3)}^{2} }

\displaystyle \sf{   =  - 4 \times  1  \times   \frac{1}{ {(12)}^{3} }   \times  {(3)}^{2} }

\displaystyle \sf{   =  - 4 \times  1  \times   \frac{1}{12 \times 12 \times 12}   \times (3 \times 3 )}

\displaystyle \sf{   =  - 4 \times     \frac{1}{12 \times 4 \times 4}  }

\displaystyle \sf{   =     \frac{ - 1}{12 \times 4 }  }

\displaystyle \sf{   =     \frac{ - 1}{48 }  }

\displaystyle \sf{   =  -     \frac{1}{48 }  }

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