if m ,2m-1 and 2m+1 are three consecutive terms of A.P ., then the value of m
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Answer:
m=3
Step-by-step explanation:
since these terms are in AP common difference is same
d=2m-1-m=2m+1-(2m-1)
m-1=2m+1-2m+1
m-1=2
m=2+1=3
m=3
numbers are 3,2(3)-1,2(3)+1
3,5,7
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