If m=(3x-4)/5 ; n=(x-7)/3 and 3(m+n)=13 then find the value of x
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Answer:
It two linear equations has infinitely many solutions means
a
1
/a
2
=b
1
/b
2
=c
1
/c
2
here two linear equations are
3x+4y=12 and
(m+n)x+2(m−n)y=5(m)−1
i.e,
m+n
3
=
2(m−n)
4
=
5m−1
12
6(m−n)=4(m+n).
m+n
3
=
5m−1
12
6m−6n=4m+4n 3(5m−1)=12m+12n
2m−10n=0⋯(1) 3m−12n=3⋯(2)
similarly (1)×3 & (2)×2
6m−30n=0
6m−24n=6
____________
6n=6 ⇒n=1
now from (1)2m−10=0
m=5
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