Question

If m(6,3) is a midpoint joining the line p(4,5) and q (8,y) then y=​

Answer 1

Answer:

Given : -

m ( 6, 3 ) as mid - point

i.e , in each Co-ordinate ( X & Y )

in X => ( 4 + 8 ) / 2 => 6 ( Already Given )

Now , For Y

=> ( 5 + y ) / 2 = 3

=> 5 + y = 6

=> y = 6 - 5 = 1

Answer 2

Answer:

The midpoint joining the line PQ then the value of y is equal to 1

Step-by-step explanation:

Given:  

m(6,3) is a midpoint of the line segment.

P(4,5) and Q(8,y) are the points joining the line segment.

To find: To find the value of y in the line segment

Solution:

Midpoint:

The midpoint of a line segment is known as the midpoint.

It is the centroid of the segment and of the ends, and it is equally distant from both of them. It cuts the section in half.

Given points P(4,5) and Q(8 ,y)

Midpoint of PQ = m

As middle point is half the sum of initial and final points of the line segment, for respective axis.

$x_{1}, y_{1} = (4,5)$

$x_{2}, y_{2} = (8,y)$

Midpoint = $(\frac{x_{1} + x_{2} }{2} ,\frac{y_{1} +y_{2} }{2} )$

(6,3) = $\frac{4+8}{2} , \frac{5+y}{2}$

Equate both sides

3 = $\frac{5+y}{2}$

⇒ 6 = 5 + y

⇒ 6 - 5 = y

y = 1

Final answer:

The midpoint joining the line PQ then the value of y is equal to 1

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