Question

if m=(7)^-7-(7)^7 and n=(7)^7-(-7)^-7 then find the value of m/n-n/m

Answer 1

Answer:

m= 7^-7 -(-7)^7

n=(7)^7-(-7)^-7

find the value of n/m - m/n

m=(1/7^7)+7^7

n=(7^7)+(1/7^7)

Substituting the value of mn-n/m ,we get

m/n-n/m= ((7^7+1/7^7)/(1/7^7)+7^7) - ((1/7^7 +7^7)/(7^7)+1/7^7))

=1-1

=0

Answer 2

Answer:

Answer = 0

Step-by-step explanation:

If m = 7 ^ - 7 - 7 ^ 7 and n = 7 ^ 7 - 7 ^ - 7 then find the value of m/n - n/m⁷

m= 1/7⁷ – 7⁷

n= 7⁷–1/7⁷

m/n – n/m

–[-1/7⁷+7⁷/7⁷-7⁷-1/7⁷] – –[-7⁷+1/7⁷/1/7⁷-7⁷]

-1 – (-1)

–1 + 1

=0 ans