Question

if m=77777777.....is a 99digit number & n= 9999999........is a 77digit number,then the sum of digits in the product of m×n is what?​

Answer 1

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Answer 2

$\huge\colorbox{pink}{Solution:-࿐ }$

Heya Mate

(•) Let's do it the un-done way !

∆ There's an interesting fact about numbers...

Say, there's a number (abcd) where a,b,c,d are digits ! Kay !

Now, if you remember correctly +_+ that is, if you do at all ^^"

# DIVISIBILITY RULE BY "9"

-> A number is divisible by 9 if and only if the sum of its digits is divisible by 9

____________________________________

(lol)

Now, we have ( mn ) = 9 ( 111111 .... 11 )( 7777777... )

=> ( mn ) is divisible by 9

And so, sum of digits is also divisible by 9 but, the only Option divisible by 9 is -> ( B )

=> Sum of digits is 891