if m = a^⅓ + a^-⅓, prove that m³-3m = a+ ¹/a
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(a+b)³=a³+b³+3ab(a+b)
Hence,
m³=(a⅓+a-⅓)³=a+1/a+3(a⅓+a-⅓)
=a+1/a+3m
LHS, m³-3m=a+1/a+3m-3m
=a+1/a = RHS
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