If M^aL^bT^c is the dimensional formula of force, find the value of 2a-b-c
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Answer:
Value of 2a-b-c=3
Explanation:
Dimensional formulae of F=[M^1L^1T^-2]
Therefore, a=1,b=2,c= - 2
2a-b-c=2(1)-1-(-2)
=2-1+2
=3
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