Question

If m and e are the mass and charge of the revolving electron in the orbit of radius r for hydrogen atom , the total energy of the revolving electron will be :



(a)12e2r(b)−e2r(c)me2r(d)−12e2

Answer 1

total energy = kinetic energy + potential energy

=e^2/2r+(-e^2/r)

=-e^2/2r

Answer 2

Answer:

Explanation:

The total energy of a revolving electron is the sum of its both the kinetic and potential energy.

Thus, total energy = K.E. + P. E

Kinetic energy = KE = 1/2 mv²

Potential energy = PE = Potential × Charge

= (KZe) ( - e)/r

Since, the centrifugal force balances the attraction between the electron and proton, thus -

mv²/r = KZe² / r²

KE = 1/2 KZe² / r²

PE = - KZe² / r²

Therefore the total energy will be =

- 1/2 KZe² / r² ( where z =1 for hydrogen (H)