Question

if m and n are any two Integers such that m>n then what should be the Pythagorean triplet from by these two Integers​

Answer 1

Answer:

4and 5

Step-by-step explanation:

Pythagorean triplets

1)3,4 and 5

2)5,12 and 13

3)7, 24,and 25

Answer 2

Given:

if m and n are any two Integers such that $m>n$.

To find: write the pythagorean triplet for the given integers.

Solution:

Know that,

A Pythagorean triple consists of three positive integers a, b, and c, such that $a^{2} + b^{2} = c^{2}.$

Assume that, $a=m,b=n$.

$\[\begin{array}{l}{c^2} = {a^2} + {b^2}\\ \Rightarrow {c^2} = {m^2} + {n^2}\\ \Rightarrow c = \sqrt {m + n} \end{array}\]$

Hence, the pythagorean triplet will be $\[m,n,\sqrt {{m^2} + {n^2}} \]$.