If m and n are odd positive integers, then m2 + n2 is even, but not divisible by 4. Justify. (3 marks)
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let m = 2 x + 1 and n = 2 y + 1 where x and y are non-negative integers.
m² + n² = (2x+1)² + (2y+1)²
= 4 x² + 4x + 1 + 4 y² + 4y + 1
= 4 (x² + y² + x + y ) + 2
So when m² + n² is divided by 4, then we get a reminder of 2 and
a quotient of (x² + y² + x + y ).
So m² + n² is divisible by 4
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hence it solved
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