If m and n are odd positive integers, then prove that m2 + n2 is even, but not divisible by
4.
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let m = 2 x + 1
and n = 2 y + 1
(where x and y are non-negative integers.)
m² + n² = (2x+1)² + (2y+1)²
m² + n² = 4 x² + 4x + 1 + 4 y² + 4y + 1
m² + n² = 4 (x² + y² + x + y ) + 2
now divide m² + n² by 4, then we get a reminder 2 and quotient (x² + y² + x + y ).
So m² + n² is divisible by 4
and n = 2 y + 1
(where x and y are non-negative integers.)
m² + n² = (2x+1)² + (2y+1)²
m² + n² = 4 x² + 4x + 1 + 4 y² + 4y + 1
m² + n² = 4 (x² + y² + x + y ) + 2
now divide m² + n² by 4, then we get a reminder 2 and quotient (x² + y² + x + y ).
So m² + n² is divisible by 4
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