Math, asked by Shwethasunil87, 11 months ago

If m and n are roots of equation x2-6x+2=0 then the value of (m+n) mn is

Answers

Answered by jinadevkv
16

Answer:

The quadratic equations are in the form x² - Sx + P = 0

where, S is the sum of roots ad P is the product of roots.

If m and n are roots of the equation x² - 6x + 2 = 0

then m+n = 6 and mn = 2

So, (m+n)*mn = 6*2 = 12

12 is your answer

Answered by vigyan260
7

Answer:

-(b) +_(√b^2-4ac)/2a

6+_(√36-8)/2

6+(√28)/2 and 6-(√28)/2

(3+√7) and (3-√7)

(m+n)mn=m^2n+mn^2

=(3+√7)^2(3-√7)+(3+√7)(3-√7)

=12

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