Question

If M and N are the mid points of the sides AB and AC of an isosceles triangle ABC and if MN|| BC find the perimeter of ∆ ABC

Answer 1

Answer:

I don't know

Step-by-step explanation:

Ab AC Ab cd. Hope it help you

Answer 2

2 ( perimeter of ΔAMN)

Explanation:

Given,

If M and N are the mid points of the sides AB and AC of an isosceles triangle ABC.

MN ║ BC  is parallel.

Find,

Perimeter of ΔABC

Hence,

By using similar triangle properties

⇒$\frac{AM}{AB}$ = $\frac{AN}{AC}$ = $\frac{MN}{BC}$-----------(1)

⇒$\frac{AM}{MB}$ = $\frac{AN}{NC}$

⇒MB = NC

⇒$\frac{1}{2}$ = $\frac{MN}{BC}$

⇒BC = 2 MN

Perimeter of ΔABC = AB + BC + AC

                                = 2 AM + 2 AN + 2 MN

                                = 2( AM +AN + MN)

                                = 2( perimeter of ΔAMN )