if m and n are the root of the equation x^2-5x+3=0, find the value of (m+n)^+ (m=n)^
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Step-by-step explanation:
x^2-5x+3=0
a=1,b=-5,(=3
m+n=-b/a = -(5)/1=5
m+n =c/a = 3/1 =3
1). (m+n)^2+(m-n)^2 =(m+n)^2+
[ ( m+n)^2 -4mn]
=5^2+5^2 -4(3)
=25+25-12
=50-12
=38
2). (m+n)^3+4mn= (5)^3+4(3)
=125+12
=137
ANSWER =137
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