Math, asked by Adityaadi7499, 1 month ago

if m and n are the root of the equation x^2-5x+3=0, find the value of (m+n)^+ (m=n)^

Answers

Answered by luckysampu11
0

Step-by-step explanation:

x^2-5x+3=0

a=1,b=-5,(=3

m+n=-b/a = -(5)/1=5

m+n =c/a = 3/1 =3

1). (m+n)^2+(m-n)^2 =(m+n)^2+

[ ( m+n)^2 -4mn]

=5^2+5^2 -4(3)

=25+25-12

=50-12

=38

2). (m+n)^3+4mn= (5)^3+4(3)

=125+12

=137

ANSWER =137

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