Question

If m and n are the zeroes of the polynomial 3^3 + 11 − 4, ℎ m/n+n/m​

Answer 1

m/n+n/m

m^2+n^2/mm

(m+n)^2-mn/mm

m/n+n/m=(m+n)^2/mn-1

sum of zeroes=m+n=-b/a=-11/3

p product of zeroes=c/a=-4/3

therefore , m/n+n/m=(-11/3)^2/(-4/3)-1=-121/16-1=-137/16

hence the value of m/n+n/m will be -137/16