Math, asked by mosharrafkhan708, 11 months ago

if m and n are the zeroes of the polynomial.f(c)=6x²+x-2, find the value of m/n+n/m​

Answers

Answered by RoyalBrothers
0

Step-by-step explanation:

Brainly.in

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Secondary School Math 5 points

Find the zeroes of the polynomial x^2+1/6x-2 and verify the realtion between the coefficient and zeroes of the polynomial.

Ask for details Follow Report by Aryabhattamadeithard 17.05.2018

Answers

KunalVerma911

KunalVerma911 Expert

Here the given equation is

x²+(1/6x)-2=0

multiplying the above equation by 6 we get

6x²+x-12=0

or,6x²+9x-8x-12=0

or,3x(2x+3)-4(2x+3)=0

or,(3x-4)(2x+3)=0

Hence the zeros of the polynomial are

x=4/3 andx=-3/2

Now for a quadratic polynomial

ax²+bx+c=0

the relation between coefficient a b and c and their roots m and n are

m+n=-b/a

mn=c/a

For the given equation

m=4/3 n=-3/2

and a=1,b=1/6 and c=-2

now m+n=-1/6

and -b/a=-1/6

therefore,m+n=-b/a

also m x n=-2

and c/a=-2

Hence m x n=c/a

Hence the relation between the coefficients of polynomial and its roots (or zeros) are verified.

hope this will help you

Answered by phanisarandhataram
0

Answer:

-25/12

Step-by-step explanation:

6x2-3x+4x-2

3x(2x-1)+2(2x-1)

(3x+2)(2x-1)

m=-2/3;n=1/2

((-2/3)÷(1/2))+((1/2)÷(-2/3))

(-4/3)+(3÷-4)

(-16+(-9))/12

"-25/12"

I think it maybe correct

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