if m and n are the zeroes of the polynomial.f(c)=6x²+x-2, find the value of m/n+n/m
Answers
Step-by-step explanation:
Brainly.in
What is your question?
1
Secondary School Math 5 points
Find the zeroes of the polynomial x^2+1/6x-2 and verify the realtion between the coefficient and zeroes of the polynomial.
Ask for details Follow Report by Aryabhattamadeithard 17.05.2018
Answers
KunalVerma911
KunalVerma911 Expert
Here the given equation is
x²+(1/6x)-2=0
multiplying the above equation by 6 we get
6x²+x-12=0
or,6x²+9x-8x-12=0
or,3x(2x+3)-4(2x+3)=0
or,(3x-4)(2x+3)=0
Hence the zeros of the polynomial are
x=4/3 andx=-3/2
Now for a quadratic polynomial
ax²+bx+c=0
the relation between coefficient a b and c and their roots m and n are
m+n=-b/a
mn=c/a
For the given equation
m=4/3 n=-3/2
and a=1,b=1/6 and c=-2
now m+n=-1/6
and -b/a=-1/6
therefore,m+n=-b/a
also m x n=-2
and c/a=-2
Hence m x n=c/a
Hence the relation between the coefficients of polynomial and its roots (or zeros) are verified.
hope this will help you
Answer:
-25/12
Step-by-step explanation:
6x2-3x+4x-2
3x(2x-1)+2(2x-1)
(3x+2)(2x-1)
m=-2/3;n=1/2
((-2/3)÷(1/2))+((1/2)÷(-2/3))
(-4/3)+(3÷-4)
(-16+(-9))/12
"-25/12"
I think it maybe correct