if m and n are the zeroes of x2 + 5x + 6 then the value of m2n + mn2 is a.5/6 b.11/30 c.6/5 d.-5/6
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Answer:
-30
Step-by-step explanation:
Given polynomial,
x² + 5x + 6
Comparing it with ax²+bx+c,we get a =1, b= 5, c= 6
Given, its zeros are m and n
Thus, m+n = -b/a and mn = c/a
or m+n = -5 and mn = 6
Cubing both sides,
(m+n)³ = (-5)³
or m³ + n³ +3 m²n + 3 m n² = -125 ...........(1)
Use the identity,
m³+n³ = (m+n)(m²+n²-m n)
or m³+n³ = (m+n){(m+n)²-3mn}
or m³+n³ = (-5){(-5)²-3(6)}
or m³+n³ = (-5)(25-18)
or m³+n³ = (-5)(7) = -35
Substituting in equation (1),
-35 + 3(m²n+mn²) = -125
or 3(m²n+mn²) = -90
or m²n + mn² = -30
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choco64:
but it does not match with any optioms
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