If m and n are the zeros of a quadratic polynomial such that m + n = 24 and m – n = 8, then find a polynomial whose zeroes are 2m and 2n.
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Step-by-step explanation:
First let us find the values of m and n
m+n= 24. ------(1)
m-n=8 ------(2)
adding equation (1) and (2)
we get,
m= 16 and n= 8
now we have to find the equation whose roots are 2m and 2n i.e 32 ,16 respectively.
we know that if a and b are roots of a equation then the equation is
x² -(a+b)x +ab=0
so our equation will be
x² -(32+16)x +32×16=0
x²-48x + 512=0
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