If m and n are the zeros of the polynomial 3x square + 11x -4 , find m/n + n/m
Answers
Answered by
2
m/n+n/m = m+n/mn
m+n = -11/3
mn=-4/3
-11/3*3/-4
11/4
ans= 11/4
m+n = -11/3
mn=-4/3
-11/3*3/-4
11/4
ans= 11/4
Answered by
5
Hey
Here is your answer,
3x^2 +11x -4 =0
Sum of zeroes = -b/a
m+n = -11/3
Product of zeroes = c/a
mn=-4/3
= m/n+n/m
=m^2 + n^2 /mn
=(m+n)^2-2mn/mn
=(-11/3)^2 -2x-4/3 / -4/3
=121/9 +8/3. / -4/3
= 121+24/9 / -4/3
=145/9 / -4/3
=-145/12
Hope it helps you!
Here is your answer,
3x^2 +11x -4 =0
Sum of zeroes = -b/a
m+n = -11/3
Product of zeroes = c/a
mn=-4/3
= m/n+n/m
=m^2 + n^2 /mn
=(m+n)^2-2mn/mn
=(-11/3)^2 -2x-4/3 / -4/3
=121/9 +8/3. / -4/3
= 121+24/9 / -4/3
=145/9 / -4/3
=-145/12
Hope it helps you!
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