Math, asked by mushreenidhi3, 1 month ago

If m and n are the zeros of the polynomial 6y^2-7y+2 find a quadratic polynomial whose zeros are 1/m and 1/n

Answers

Answered by mahaksingh589
1

Answer:

7y^2-49x+6

Step-by-step explanation:

m+n= 7/6

mn= 2/6 = 1/3

1/m+1/n = m+n/mn = 7/6÷1/6 = 7

1/m*1/n= 1/mn= 1÷7/6 = 6/7

polynomial = k(y^2-7x+ 6/7)

let k=7 = 7y^2-49x+6

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