If m and n are the zeros of the polynomial 6y^2-7y+2 find a quadratic polynomial whose zeros are 1/m and 1/n
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Answer:
7y^2-49x+6
Step-by-step explanation:
m+n= 7/6
mn= 2/6 = 1/3
1/m+1/n = m+n/mn = 7/6÷1/6 = 7
1/m*1/n= 1/mn= 1÷7/6 = 6/7
polynomial = k(y^2-7x+ 6/7)
let k=7 = 7y^2-49x+6
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