Question

If M and N are two elements having atomic number 13 and 16. What will be the sum of electron present in their M shells

Answer 1

Answer:

Electronic configuration of Cr (atomic number 24) =[Ne]3s

2

3p

6

3d

5

4s

1

Therefore number of electrons in M shell (third shell) =2+6+5=13.

Answer 2

Given,

• M = Element with atomic number 13

• N = Element with atomic number 16

Here,

• M = Aluminum (Al)

• N = Sulphur (S)

So,

• Electronic configuration of Al = [Ne] 3s² 3p¹

• Electronic configuration of S = [Ne] 3s² 3p⁴

Therefore,

• Number of electrons in M shell of Al = 2 + 1 = 3

• Number of electrons in M shell of S = 2 + 4 = 6

Number of electrons in M shell of Aluminum = 3

Number of electrons in M shell of Sulphur = 6