Question

If m and n are two numbers such that m + n = 3 and m - n = 19, then what is the quadratic polynomial whose zeroes are m and n?​

Answer 1

Answer:

x²-3x-88=0

Step-by-step explanation:

explaination is inthe picture, every equation assumed is taken comparing to the quadratic equation (ax²+bx+c=0)

Answer 2

Answer:

hey mate here is your answer.....

Step-by-step explanation:

▶️Given m and n are zeroes of polynomial such that m+n=3 and m -n=19

➡️ let m+n=3 be eq. (1) and m -n=19 be eq. (2)

➡️let us add eq (1) and (2)

➡️ (m + n) + (m - n) = 3 + 19

➡️ 2m = 22 so m = 11

▶️Now let us put value of m in eq(1)

➡️ m + n = 3

➡️ n = 3 - 11

➡️ n = -8

☑️ So the zeroes of the polynomial are 11 and -8 respectively.

☑️For finding quadratic polynomial..

• ( x + 8 ) ( x - 11 )
• x ( x + 8 ) - 11 ( x + 8)
• x² + 8x - 11x - 88
• x² - 3x - 88

Hope it helps! ☺️