Question

If m and n are whole numbers such that m^n = 121 find (m-n)^n+1​

Answer 1

Answer:

729

Step-by-step explanation:

11^2=121

m=11,n=2

m-n=9, n+1=3

so that 9^3=729

Answer 2

${11}^{2} = 121$

$therefore \: m = 11 \: n = 2$

$(m - 1)$

$m - {1}^{n} + 1 = (11 - 1) ^{(2 + 1)}$

${10}^{3} = 1000$