If m and n are zeroes of kx2 -2x +3k such that m+ n = mn then k =? *
1 point
(a) 1/3
(b) -1/3
(c) 2/3
(d) -2/3
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Answer: k = ⅔ (c).
Explanation:
Let, p(x) = kx² - 2x + 3k
And, m and n are the zeroes and it is given that,
m + m = mn
=> - b/a = c/a
(Vieta's formulae)
=> c = - b
=> 3k = - (- 2)
=> k = ⅔.
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