Math, asked by raktesarvesh, 10 months ago

If m and n are zeroes of the polynomial x^2-5x+6 , find m^2n+n^2m​

Answers

Answered by tejamonster
0

Answer:m^2n+n^2m=37/36

Step-by-step explanation:x^2-5x+6=0

x ^2+x-6x+6=0

x  (x +1)-6 (x +1)=0

(x+1)or (x-6)=0

x +1=0,x-6=0

x =-1,x =6

Zeroes are -1,6then we get,m=-1,n=6

m^2n+n^2m=(-1)^2×6+(6)^2 (-1)

=(-1)^12+(6)^2×-1

=1+6^-2     (since a-^2=1/a^2)

=1+1/6^2

=1+1/36

=36+1/36=37 /36

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