If m be the volume of cone and n be the curved surface area of a cone of dimensions p, q and r where p is the radius, q is the height and r is the slant height of a cone, then 1/m is equal to
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heyy .
your solution is....
1/m is given by ....
1/m = 1/ (volume of cone).
1/m=1/((1/3)*πr^2*h)).
which comes out to be....
(3/πr^2*h)..
in terms of given notation ..
1/m is (3/π*p^2*r)....
..# [ ^ resembles: raise to , or power of .]
(* resembles :multiplied by)
your solution is....
1/m is given by ....
1/m = 1/ (volume of cone).
1/m=1/((1/3)*πr^2*h)).
which comes out to be....
(3/πr^2*h)..
in terms of given notation ..
1/m is (3/π*p^2*r)....
..# [ ^ resembles: raise to , or power of .]
(* resembles :multiplied by)
Answered by
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sorry, I don't know this answer... :-( :-(
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