Math, asked by ayushmanarman, 4 months ago

If m = cosA - sinA and n = cosA + sinA, then prove that √m/√n+√n/√m=2/√1-tan²a

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Answered by sakshi200736

Answer:

m= cosA-sinA and n= cosA++ sinA.show that ... n= cosA++sinA.show that √m/n+ √n/m=2/√1-tan^A. 2. See answers ... 2 cosA/√ cos²A(1-sin²A/cos²A). => 2/√(1-tan²A).

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If m = cosA - sinA and n = cosA + sinA, then prove that √m/√n+√n/√m=2/√1-tan²a​

Answers

If m = cosA - sinA and n = cosA + sinA, then prove that √m/√n+√n/√m=2/√1-tan²a