if m cot A=n find the value of
m sin A-n cosA/n cos A+m sin A
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Answered by
0
Step-by-step explanation:
Given mcotA=n⟹cotA=
m
n
ncosA+msinA
msinA−ncosA
=
n
sinA
cosA
+m
m−n
sinA
cosA
=
m+ncotA
m−ncotA
=
m+n×
m
n
m−n×
m
n
=
n
2
+m
2
n
2
−m
2
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