if m is an even number prove that m^2 is a multiple of 4
pls answer it in this format
m Is an even number so m=2n
n is an integer
m^2 =(2n)^2 = 4^2
since n is an integer n^2 is an integer
m^2 = 4n
so let us call 4n k
m^2 = k
k is divisible by 4
so m^2 is a factor of k
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