if 'm' is the mass of a body, 'v' it's velocity and 'p' the momentum then write a relationship between change in momentum , mass and velocity of the body when - 1) v is almost equal to c . the velocity of light .2) v is very less as compare to c . the velocity of light.
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1) when the velocity is equal to c :
∆p(change in momentum)= ∆(mass*velocity)
as mass differs with velocity as per the expression m=m(rest mass)/√1-v²/c so Delta sign would also apply to mass
2) when v<<c
∆p=m∆v
as the velocity is very less compared to c
then mass hardly changes so there is no need to add Delta∆ sign in front of m
∆p(change in momentum)= ∆(mass*velocity)
as mass differs with velocity as per the expression m=m(rest mass)/√1-v²/c so Delta sign would also apply to mass
2) when v<<c
∆p=m∆v
as the velocity is very less compared to c
then mass hardly changes so there is no need to add Delta∆ sign in front of m
soumyasripain:
thank you for the answer
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Answer:
1) when the velocity is equal to c :
∆p(change in momentum)= ∆(mass*velocity)
as mass differs with velocity as per the expression m=m(rest mass)/√1-v²/c so Delta sign would also apply to mass
2) when v<<c
∆p=m∆v
as the velocity is very less compared to c
then mass hardly changes so there is no need to add Delta∆ sign in front of m
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