Physics, asked by Boom4878, 11 months ago

If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius ′2r′ is:
(A) 4 M
(B) M/2
(C) M
(D) 2 M

Answers

Answered by Anonymous
38

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If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius ′2r′ is:

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see the attachment

correct option is d) 2M

I hope it helps you!

Attachments:
Answered by anshi60
7

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Height of liquid rise in capillary tube is inversely proportional to Radius .

when radius becomes double,

then height becomes half

M= πr²ᣖH

now when H'= H/2 and r'= 2r

M ' = π(2r)²ᣖ(H/2)

M' = 2M

correct option d)

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