If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius ′2r′ is:
(A) 4 M
(B) M/2
(C) M
(D) 2 M
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If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius ′2r′ is:
see the attachment
correct option is d) 2M
I hope it helps you!
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Answered by
7
Height of liquid rise in capillary tube is inversely proportional to Radius .
when radius becomes double,
then height becomes half
M= πr²ᣖH
now when H'= H/2 and r'= 2r
M ' = π(2r)²ᣖ(H/2)
M' = 2M
correct option d)
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