Question

If M is the mean of x₁, x₂, x₃, x₄, x₅ and x₆, prove that
(x₁-M)+ (x₂-M)+ (x₃-M)+ (x₄-M)+ (x₅-M)+(x₆-M) = 0.

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

M is the mean of x₁, x₂, x₃, x₄, x₅ and x₆

Mean = Sum of observation / Number of observation

M =  x₁ + x₂ + x₃ + x₄ + x₅ + x₆ / 6

6 M = x₁ + x₂ + x₃ + x₄ + x₅ + x₆

6 M - (x₁ + x₂ + x₃ + x₄ + x₅ + x₆ ) = 0

6 [(x₁-M) + (x₂-M) + (x₃-M) + (x₄-M) + (x₅-M) + (x₆-M)] = 0

Therefore, (x₁-M) + (x₂-M) + (x₃-M) + (x₄-M) + (x₅-M) + (x₆-M) = 0

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