Math, asked by adityaanand5136, 10 hours ago

If m+n=16 and m^2+n^2=400 find the value of mn

Answers

Answered by vipashyana1
1

Answer:

mn=(-72)

Step-by-step explanation:

m²+n²=400

m+n=16

Squaring on both the sides

(m+n)²=(16)²

m²+n²+2mn=256

400+2mn=256

2mn=256-400

2mn=(-144)

mn=(-144)/2

mn=(-72)

Therefore, the value of mn is (-72).

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