Math, asked by Anonymous, 6 months ago

If m – n = 16 and m^2 + n^2 = 400, then find the value of mn.

Answers

Answered by nomulasaraswathi1
1

Answer:

(m-n)²=m²+n²-2mn

16²=400-2mn

256=400-2mn

144=2mn

mn=72

therefore the value of mn=72

Answered by afia30
1

Answer:

square both sides of equation 1.

m^2+n^2-2mn=16^2

put the value of m^2+n^2 as 400 and solve it

hope it will help you

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