if m+n=16 and mn=7 find m2+n2
Answers
Answered by
10
Hey
Here is your answer,
Given that,
m+n = 16
mn = 7
By using the identity ( m+n )^2 = m^2 + n^2 + 2mn
( m+n )^2 = m^2 + n^2 + 2mn
m^2 + n^2 = (m+n)^2 - 2mn
m^2 + n^2 = (16)^2 - 7
= 256 - 7
= 249
Hope it helps you!
Here is your answer,
Given that,
m+n = 16
mn = 7
By using the identity ( m+n )^2 = m^2 + n^2 + 2mn
( m+n )^2 = m^2 + n^2 + 2mn
m^2 + n^2 = (m+n)^2 - 2mn
m^2 + n^2 = (16)^2 - 7
= 256 - 7
= 249
Hope it helps you!
cuteGmail:
can you please help me
Answered by
0
Answer:
The answer is quite easy, it is 256
Step-by-step explanation:
m+n=16
m^2+n^2=(m+n)^2
(m+n)^2=16^2=256
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