If m n = ( −2 9 ) 9 ÷ ( −2 9 ) 7 then find ( m n ) 2
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m4n4×6m2n2×3m2n2=(mn)k
⇒(mn)4/2×(mn)2/6×(mn)2/3=(mn)k
⇒(mn)2+31+32=(mn)k
⇒k=2+31+32
∴ k=3.
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