If m+n=2, mn=-2, find m^2+n^2
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Answered by
0
Given
m + n = 2 & mn = 2
We know that,
(a + b)^2 = a^2 + b^2 + 2ab
Rearranging the above equation, we get
a^2 + b^2 = (a + b)^2 - 2ab
Therefore
m^2 + n^2 = (m + n)^2 - 2*mn
m^2 + n^2 = 2^2 - 2*2
m^2 + n^2 = 4 - 4 = 0 ——> Answer
m + n = 2 & mn = 2
We know that,
(a + b)^2 = a^2 + b^2 + 2ab
Rearranging the above equation, we get
a^2 + b^2 = (a + b)^2 - 2ab
Therefore
m^2 + n^2 = (m + n)^2 - 2*mn
m^2 + n^2 = 2^2 - 2*2
m^2 + n^2 = 4 - 4 = 0 ——> Answer
Answered by
0
Answer:
m + n = 2
(m+n)²= 2²
m²+n²+2mn =4
m²+n²+2*-2 = 4
m²+n²= 4+4 = 8
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