If m^n =32 and m,n are natural numbers, then find the value of n^mn
Answers
Answered by
68
Hey!
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Correct Question -
m^n = 32 , then n^m ?
We know,
32 = 2^5
Then,
m^5 = 2^5
m = 2 and n = 5
Then,
n ^ m = 5 ^ 2
5^2 = 25
_________________
Hope it helps...!!!
_______________
Correct Question -
m^n = 32 , then n^m ?
We know,
32 = 2^5
Then,
m^5 = 2^5
m = 2 and n = 5
Then,
n ^ m = 5 ^ 2
5^2 = 25
_________________
Hope it helps...!!!
Answered by
55
Heya.....!!!!
___________________________
** There is a correction in your question in last line - it's n^m .
Given in the question :-
• m^n = 32.
m, n are natural numbers.
So , we know that => 2^5 = 32
comparing 2^5 with m^n .
=> m = 2
=> n = 5 .
We have to find The value of :- n^m .
putting value of m and n ,, we get :
=> 5^2
=> 5 × 5
➡ 25 is the required answer .
===============================
Hope It Helps You ☺
___________________________
** There is a correction in your question in last line - it's n^m .
Given in the question :-
• m^n = 32.
m, n are natural numbers.
So , we know that => 2^5 = 32
comparing 2^5 with m^n .
=> m = 2
=> n = 5 .
We have to find The value of :- n^m .
putting value of m and n ,, we get :
=> 5^2
=> 5 × 5
➡ 25 is the required answer .
===============================
Hope It Helps You ☺
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