Math, asked by onkarduttdevlal, 1 year ago

If m^n =32 and m,n are natural numbers, then find the value of n^mn

Answers

Answered by Nikki57
68
Hey!

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Correct Question -

m^n = 32 , then n^m ?

We know,

32 = 2^5

Then,

m^5 = 2^5

m = 2 and n = 5



Then,

n ^ m = 5 ^ 2

5^2 = 25

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Hope it helps...!!!
Answered by rohit710
55
Heya.....!!!!

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** There is a correction in your question in last line - it's n^m .


Given in the question :-

• m^n = 32.

m, n are natural numbers.

So , we know that => 2^5 = 32

comparing 2^5 with m^n .

=> m = 2
=> n = 5 .

We have to find The value of :- n^m .

putting value of m and n ,, we get :

=> 5^2
=> 5 × 5

➡ 25 is the required answer .


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Hope It Helps You ☺
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