If m^n=32 where M and n are natural numbers then find the value of n^m
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Answered by
1
m^n = 32
32 = 2 × 2 × 2 × 2 × 2
= 2^5
so m = 2
n = 5
n^m = 5^2
= 5 × 5
= 25
32 = 2 × 2 × 2 × 2 × 2
= 2^5
so m = 2
n = 5
n^m = 5^2
= 5 × 5
= 25
Answered by
0
m^n=32
i.e m^n = 2^5
so m = 2 and n = 5
hence,
n^m = 5^2 = 25
i.e m^n = 2^5
so m = 2 and n = 5
hence,
n^m = 5^2 = 25
Anonymous:
hello
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