Math, asked by mamonisarkarankit, 9 months ago

if m+n=5 and mn=6 then find (m²+n²)(m³+n³)

Answers

Answered by kkee
2

(m+n)²=m²+n²+2mn

m²+n²= (m+n)²-2mn

=5² - 2(6)

= 25 - 12

m²+n²= 13

(m+n)³=m³+n³+3mn(m+n)

m³+n³= (m+n)³-3mn(m+n)

= 5³-3(6)(5)

= 125 - 90

m³+n³= 35

(m²+n²)(m³+n³) = 13×35

=455

Hope it helps you

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Answered by sandy1816
0

given \:  \:  \:  \:  \: m + n =5 \\   \:  \:  \:  \:  \:  \:  \:  \: mn = 6 \\  \\  {m}^{2}  +  {n}^{2}  = ( {m + n})^{2}  - 2mn \\  =  {5}^{2}  - 2 \times 6 \\  = 25 - 12 \\  = 13 \\  \\  {m}^{3}  +  {n}^{3}  = ( {m + n})^{3}  - 3mn(m + n) \\  =  {5}^{3}  - 3 \times 6 \times 5 \\  = 125 - 90 \\  = 35 \\  \\ ( {m}^{2}  +  {n}^{2} )( {m}^{3}  +  {n}^{3} ) = 13 \times 35 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 455

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