Question

If m+n=9 and mn=16, find the value of (m^2+n^2)​

Answer 1

Answer:

using identity a^2 + b^2 we have

(a+b)^2 + 2ab

where a+b = m+n

and ab= mn

(m+n)^2 +2mn

it is given that m+n = 9 and mn=16,putting these values in (m+n)^2 +2mn we get,

9^2 +2 x 16

81+32

113

mrk me as brainliest if my answer is correct

Answer 2

Answer:

${m}^{2} + {n}^{2} = {(m + n)}^{2} - 2mn = {9}^{2} - (2 \times 16) = 81 - 32 =49 {ans}$