If m # n and (m + n)-1 (m-' + n-1) = m'n';
show that : x + y + 2 = 0.
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Step-by-step explanation:
(m+n)−1(m−1+n−1)=mxny
L.H.S.
=m+n1(m1+n1)
=(m+n1)(nmn+m)
=nm1=m−1n−1
R.H.S =mxny
⇒x=−1&y=1
⇒x+y+2=(−1)+(−1)+2=0
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