If m,n are natural numbers ,for what values of m,does 2^×5^ ends in 5
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2n is always even for all values of n. 5m is always odd and ends with 5 for all values of m. But 2n × 5m is always even and ends in 0. ∴ 2n × 5m cannot end with the digit 5 for any values of m.
Answered by
1
Answer:
2n is always even for all values of n. 5m is always odd and ends with 5 for all values of m. But 2n × 5m is always even and ends in 0. ∴ 2n × 5m cannot end with the digit 5 for any values of m.
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